Prove that (cosecA - sin A)(sec A -cos A) secA= tan A
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I think in Right hand side it should be sinA not tanA
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Anudeeprag0306:
yes you are right
no ot is not right
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hey mate here is ur answer
(1/sinA - sinA)(1/cosA - cosA) sec square A
1-sin square A/sinA * 1-COS square A/ cosA * 1/cos square A
cos square A/sinA * sin squareA/ cosA * 1/cos square A
=tanA
hope it helps you
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pls mark me as a brainlist
but in the question it is mentioned as secA but not sec^2 A so the answer must be tanA/secA =tanA×cos A = sinA
yes it is right
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