Prove that
( cosecA-sinA ) ( secA-cosA ) = 1÷tanA+cotA
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open both sides and you get answer....
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gwadhwa2003:
Thank u for the answer
Answered by
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Answer:
here this:
Step-by-step explanation:
(cosA-sin A)x(secA-cosA)=(1-Sin^2A/sinA)x(1-cos^2A/cosA)
=cosAsinA ....(1)
1÷tanA+cotA=cosAsinA/Sin^2A+cos^2A=cosAsinA.....(2)
Compare these two equations we get LHS+RHS proved.
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