Question

Prove that
( cosecA-sinA ) ( secA-cosA ) = 1÷tanA+cotA

Answer 1

open both sides and you get answer....

Answer 2

Answer:

here this:

Step-by-step explanation:

(cosA-sin A)x(secA-cosA)=(1-Sin^2A/sinA)x(1-cos^2A/cosA)

=cosAsinA     ....(1)

1÷tanA+cotA=cosAsinA/Sin^2A+cos^2A=cosAsinA.....(2)

Compare these two equations we get LHS+RHS proved.