Prove that ( cosecA -sinA) (secA-cosA) = 1/tanA+cotA
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Answer:
Step-by-step explanation:
L.H.S
(cosecA-sinA)(secA-cosA)
=(1/sinA-sinA)(1/cosA-cosA)
=(1-sin^A/sinA)(1-cos^A)
=cos^A/sinA*sin^A/cosA
=cosA*sinA
R.H.S
1/tanA+cotA
=1/sinA/cosA+cosA/sinA
=1/sin^A+cos^A/sinAcosA
=1/1/sinAcosA
=sinAcosA
L.H.S=R.H.S
Hence Proved
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