Question

Prove that
cot (180°+0) sin (90°-O) cos (-0)
sin (270°+0) tan (-0) cosec (360° +0)
= cos? 0 cot 0.
​

Answer 1

Answer:

sin(1800+θ)=−sinθ, cos(900+θ)=−sinθ, tan(2700−θ)=cotθ,

cot(3600−θ)=−cotθ, sin(3600−θ)=−sinθ, cos(3600+θ)=cosθ,

cosec(−θ)=−cosecθ,sin(2700+θ)=−cosθ.

∴    given exp. = (−sinθ).cosθ(−cosecθ)(−cosθ)(−sinθ).(−sinθ).cotθ(−cotθ)=1