prove that cot^2 theta - cos^2 theta = cot^2 theta . cos^2 theta
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Solution:
Here I am using A instead of theta.
LHS = cot² A -cos²A
= (cos²A/sin²A) - cos²A
= cos²A( 1/sin²A - 1 )
= cos²A [(1-sin²A)/sin²A]
= (cos²A/sin²A) × cos²A
= cot²A×cos²A
= RHS
••••
Answered by
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here is the answer.................
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