Question

Prove that:- cot 90-∅).sin(90-∅)/sin∅+cot 40/tan 50 – (cos²20+cos²70)=1

Answer 1

Hi there!

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Gm

Ur soln:

✌Lhs

cot 90-∅).sin(90-∅)/sin∅+cot 40/tan 50 – (cos²20+cos²70)

=tan ∅. Cos ∅/sin ∅ + cot(90°-50°)/tan50° - [cos² (90°-70°)+ cos²70 ]

=tan ∅.cot ∅+tan50°/tan50°-[sin ² 70°+ cos²70 °]

=tan ∅. 1/tan ∅+1-1

=1+1-1

=1

=Rhs✌

PROVED

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Hope it helps ya buddy