Question

prove that cot(90-theta)/tan theta + cosec(90-theta) sin theta / tan(90-theta)=sec²theta​

Answer 1

Answer:

Let theta be A

LHS - tan A / tan A + sec A . sin A / cot A

1 + sin^2 A / cos^2 A

Taking on the LCM we get,

cos^2 A + sin^2 A / cos^2 A = 0

Using the identity,

cos^2 A + sin^2 A = 1

1 / cos^2 A = sec^2 A

RHS - sec^2 A

Hence proved

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