prove that (cot A+sec B)² -(tan B - cosec A)² = 2(cot A . sec B + tan B . cosec A)
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Answered by
37
Step-by-step explanation:
(cotA+secB)²-(tanB-cosecA)²
=cot²A+sec²B+2cotAsecB-tan²B-cosec²A+2tanBcosecA
=cot²A-cosec²A+sec²B-tan²B + 2(cotAsecB+tanBcosecA)
=-1+1+2(cotAsecB+tanAcosecA)
=2(cotAsecB+tanBcosecA)
Answered by
7
Answer:
(cotA+secB)²-(tanB-cosecA)²
=cot²A+sec²B+2cotAsecB-tan²B-cosec²A+2tanBcosecA
=cot²A-cosec²A+sec²B-tan²B + 2(cotAsecB+tanBcosecA)
=-1+1+2(cotAsecB+tanAcosecA)
=2(cotAsecB+tanBcosecA)
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