Math, asked by anuragshukl235, 9 months ago

Prove that : cot A + tan (180° – A) + tan (90° + A) + tan (360° + A) = 0.

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Answered by sweetgirl50

Answer:

$\cot(a) + \tan(180 - a) + \tan(90 + a) + \tan(360 - a)$

Answered by Jarya132004

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Prove that : cot A + tan (180° – A) + tan (90° + A) + tan (360° + A) = 0.​

Answers

Prove that : cot A + tan (180° – A) + tan (90° + A) + tan (360° + A) = 0.