Question

prove that cot square A in bracket sec a minus 1 upon 1 + sin a + sin square A in bracket Sin A minus 1 upon 1 + 1 sec a = 0​

Answer 1

Answer:

proven

Step-by-step explanation:

oneone we can write this in square + cos square by adding with sin square a + cos square b got the 2 on the second square to 1 is equal to x square minus secant squared by this we got 0