Question

prove that (cot theta -cosec theta)^2= 1-cos theta/1+cos theta

Answer 1

Answer:

Since #csctheta=1/sintheta and cottheta=costheta/(sintheta)#,

you can substitute and have:

#(csctheta-cottheta)^2=(1/sintheta-costheta/(sintheta))^2#

#=((1-costheta)/(sintheta))^2=(1-costheta)^2/(sin^2theta)#

Since #sin^2theta=1-cos^2theta#, the expression becomes:

#=(1-costheta)^2/(1-cos^2theta)=(1-costheta)^cancel2/(cancel((1-costheta))(1+costheta))=(1-costheta)/(1+costheta)#

and the identity is verified

Step-by-step explanation:

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