prove that cot theta -cot 2theta = cosec2 theta
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1
Answer:Taking LHS=sec
2
θ+cosec
2
θ
=
cos
2
θ
1
+
sin
2
θ
1
[∵cosθ=
secθ
1
];[sinθ=
cosecθ
1
]
=
cos
2
θsin
2
θ
sin
2
θ+cos
2
θ
[∵cos
2
θ+sin
2
θ=1]
=
cos
2
θsin
2
θ
1
=sec
2
θ.cosec
2
θ=RHS[∵cosθ=
secθ
1
];[sinθ=
cosecθ
1
]
Step-by-step explanation:
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