Math, asked by anoopsingh508, 1 year ago

Prove that cot theta tan (90- theta)-sec(90- theta)cosec theta +root 3 tan 12 tan60 tan78=2

Answers

Answered by ritikkumar53
4

Step-by-step explanation:

cot theta.cot theta-cosec theta.cosec theta+root3 (tan12.tan78.tan60)

=cot sq theta -cosec sq theta +root3 (tan12.cot12.root3)

=-1+root3×1×root3

=-1+3

=2

i hope this helps you

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