Prove that cot theta tan (90- theta)-sec(90- theta)cosec theta +root 3 tan 12 tan60 tan78=2
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Step-by-step explanation:
cot theta.cot theta-cosec theta.cosec theta+root3 (tan12.tan78.tan60)
=cot sq theta -cosec sq theta +root3 (tan12.cot12.root3)
=-1+root3×1×root3
=-1+3
=2
i hope this helps you
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