Question

Prove that sin 68/cos 22+root3(tan10 tan30 tan40 tan50 tan80 )=2

Answer 1

Answer:

sin68/sin (90-22)+root3 (tan10.tan80.tan30.tan50.tan40)

=sin68/sin68+root3 (tan10.cot10.root3.tan50.cot50

=1+root3 ×1×root3 ×1

=1+3

=4

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