prove that cot theta -tan theta =2cos^2 theta-1 ÷sintheta cos theta
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Answered by
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Answered by
42
Answer:
cot θ - tan θ = (2cos²θ - 1)/sinθcosθ
Step-by-step explanation:
Hi,
Consider L.H.S
= cot θ - tan θ
Using tan θ = sin θ/cos θ and cot θ = cos θ/sin θ,
= cosθ/sinθ - sinθ/cosθ
= (cos²θ - sin²θ)/sinθcosθ
Substituting sin²θ = 1 - cos² θ, we get
= [cos²θ - (1 - cos² θ)]/sinθcosθ
= (2cos²θ - 1)/sinθcosθ
= R.H.S
Hope, it helps !
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