Question

prove that , cotx cot2x - cot2x cot3x - cot 3x cot x = 1​

Answer 1

we know that

tan 3x tan2x tan X = tan 3x -tan 2x-tanx

dividing both sides by tan3x tan2x tan X

tan 3x tan 2x tan X / tan 3x tan 2x tan X = tan3x- tan2x - tanx / tan3x tan2x tanx

1 = 1/tan2x tanx - 1/ tan3x tan c- 1/ tan 3x tan 2x

1 = cotx cot 2x - cot3x cot x - cot3x cot2x

hence proved

Answer 2

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Step-by-step explanation:

tan 3x tan2x tan X = tan 3x -tan 2x-tanx

dividing the both sides by tan3x tan2x tan X

We get

tan 3x tan 2x tan X / tan 3x tan 2x tan X = tan3x- tan2x - tanx / tan3x tan2x tanx

1 = 1/tan2x tanx - 1/ tan3x tan c- 1/ tan 3x tan 2x

SOLVING

1 = cotx cot 2x - cot3x cot x - cot3x cot2x

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