Prove that (cotx+coty)^2 = (sinx+cosy)^2
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The question does not hold good for a correct answer because if
(cot x+cot y)²=(sin x+cos y)²
Then, cot x+cot y= sin x+ cos y
Which is not possible
Ojusoni:
sorry I write cosy instead of siny
Can you rewrite the correct question???
ohkk
prove that (cotx+coty)^2 = (sinx-siny)^2
Hey! Then also it's not possible as this would mean cot x+cot y=sin x+sin y
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