Question

prove that
(\csc( \alpha ) - \csc( \beta ) ) ^{2} + ( \sin( \alpha ) - \sin( \beta ) )^{2} = 4 \sin^{2} \frac{ \alpha - \beta }{2}(csc(α)−csc(β))
2
+(sin(α)−sin(β))
2
=4sin
2

2
α−β
​
​

Answer 1

Answer:

_______________!______/______/_

Answer 2

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