Question

prove that cube root of 6 and cube root of 3 are not irrational numbers​

Answer 1

Step-by-step explanation:

Substituting x, we get, 6 y^3 = 216 z^3 i.e. y^3 = 36 z^3; which means y^3 is divisible by 6, and so y will also be divisible by 6. Now, from theorem, x and y will have 6 as a common factor. But, it is opposite to fact that x and y are co-prime. Hence, we can conclude (cube root 6) is irrational.