Question

prove that cyclic pallogram is a rectangle ​

Answer 1

mark as brainliest answer.

Answer 2

Answer:

Step-by-step explanation:

Given: Let ABCD be a cyclic parallelogram

To prove: ABCD is a rectangle

Proof: A rectangle is a parallelogram with one angle 90⁰

So, we have to prove angle 90°

Since ABCD is a parallelogram

∠A=∠C ( Opposite angles of parallelogram are equal) (1)

In cyclic parallelogram

∠A+∠C=180°(Sum of opposite angles of a cyclic quadrilateral is 180°)

∠A+∠A=180°(From(1))

2∠A=180°

∠A=180°/2=90°