prove that determinant is a perfect square
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Assuming you are talking about matrices:
It really depends on the format of the determinant. If you just have the determinant, a single value, then good luck ever getting the matrix!
But if it is in the format ab−cdab−cd, then the square matrix is:
[adcb][acdb]
You’ll more commonly see it as
[acbd][abcd]
where the determinant is ad−bcad−bc instead
pls mark brainliest
It really depends on the format of the determinant. If you just have the determinant, a single value, then good luck ever getting the matrix!
But if it is in the format ab−cdab−cd, then the square matrix is:
[adcb][acdb]
You’ll more commonly see it as
[acbd][abcd]
where the determinant is ad−bcad−bc instead
pls mark brainliest
sejal577922:
pls mark brainliest
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714378
IT IS NOT A PERFECT
SQUARE NO
You can check by prime factorising method
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