prove that diagonal of a isosceles trapezium are congruent
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We have to know the features of an isosceles trapezium first.
In an isosceles trapezium,
⇒ One pair of opposite sides are equal but not parallel.
⇒ One pair of opposite sides are parallel but not equal.
⇒ Angles on either end of one among the parallel sides are equal.
⇒ Angles on either end of one among the equal sides are supplementary.
The proof is given below:
Consider the isosceles trapezium ABCD given in the figure.
We have to prove that AC = BD.
Consider triangles ABC and BAD.
→ AB = AB (common)
→ BC = AD
→ ∠B = ∠A
∴ ΔABC ≅ ΔBAD
∴ AC = BD
Hence Proved!!!
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