Prove that diagonal of llgm
divide it in two congreceat treagles
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Step-by-step explanation:
Each diagonal of a parallelogram divides it into two congruent triangles.
Let us consider a parallelogram ABCD where AB | CD and AD II BC.
Join AC.
In AABC and ACDA, we have
DCA = BAC
[Alternate angles]
DAC = ACB
[Alternate angles]
AC=CA
[Common)
:: ABC=CDA
[ASA congruency]
Similarly, by drawing the other diagonal BD, we can prove that AABD = ACDB.
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