Question

Prove that diagonal of rectangle are equal to each other

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Let ABCD be a rectangle.

We have to prove that AC = BD.

In the triangles ABC and DCB:

BC = CB (common)  

AB = DC   (opposite sides of a parallelogram are equal)  

ABC =DCA = 90°   (given)

so ABC =(congruent) DCB (SAS)

Hence AC=DB by CPCT

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