Question

prove that diagonals of parallelogram divide it into two congruent triangles​

Answer 1

Step-by-step explanation:

Given: A parallelogram ABCD and AC is its diagonal .

To prove : △ABC ≅ △CDA

Proof : In △ABC and △CDA, we have

∠DAC = ∠BCA [alt. int. angles, since AD | | BC]

AC = AC [common side]

and ∠BAC = ∠DAC [alt. int. angles, since AB | | DC]

∴ By ASA congruence axiom, we have

△ABC ≅ △CDA

Answer 2

In order to prove this , take a parallelogram, draw it's diagonal and then prove the congruence using SSS criteria

Hence proved.

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