Question

prove that diagonals of rectangle are equal​

Answer 1

Answer:

Given: Rectangle ABCD

Prove: segment AC ≅ segment BD

Prove: segment AC ≅ segment BDSince ABCD is a rectangle, it is also a parallelogram.

Prove: segment AC ≅ segment BDSince ABCD is a rectangle, it is also a parallelogram.Since ABCD is a parallelogram, segment AB ≅ segment DC because opposite sides of a parallelogram are congruent

Prove: segment AC ≅ segment BDSince ABCD is a rectangle, it is also a parallelogram.Since ABCD is a parallelogram, segment AB ≅ segment DC because opposite sides of a parallelogram are congruentBC ≅ BC by the Reflexive Property of Congruence.

Prove: segment AC ≅ segment BDSince ABCD is a rectangle, it is also a parallelogram.Since ABCD is a parallelogram, segment AB ≅ segment DC because opposite sides of a parallelogram are congruentBC ≅ BC by the Reflexive Property of Congruence.Furthermore, ∠ABC and ∠DCB are right angles by the definition of rectangle.

Prove: segment AC ≅ segment BDSince ABCD is a rectangle, it is also a parallelogram.Since ABCD is a parallelogram, segment AB ≅ segment DC because opposite sides of a parallelogram are congruentBC ≅ BC by the Reflexive Property of Congruence.Furthermore, ∠ABC and ∠DCB are right angles by the definition of rectangle.∠ABC ≅ ∠DCB since all right angles are congruent.

Prove: segment AC ≅ segment BDSince ABCD is a rectangle, it is also a parallelogram.Since ABCD is a parallelogram, segment AB ≅ segment DC because opposite sides of a parallelogram are congruentBC ≅ BC by the Reflexive Property of Congruence.Furthermore, ∠ABC and ∠DCB are right angles by the definition of rectangle.∠ABC ≅ ∠DCB since all right angles are congruent.Summary

Prove: segment AC ≅ segment BDSince ABCD is a rectangle, it is also a parallelogram.Since ABCD is a parallelogram, segment AB ≅ segment DC because opposite sides of a parallelogram are congruentBC ≅ BC by the Reflexive Property of Congruence.Furthermore, ∠ABC and ∠DCB are right angles by the definition of rectangle.∠ABC ≅ ∠DCB since all right angles are congruent.SummaryAB ≅ segment DC

Prove: segment AC ≅ segment BDSince ABCD is a rectangle, it is also a parallelogram.Since ABCD is a parallelogram, segment AB ≅ segment DC because opposite sides of a parallelogram are congruentBC ≅ BC by the Reflexive Property of Congruence.Furthermore, ∠ABC and ∠DCB are right angles by the definition of rectangle.∠ABC ≅ ∠DCB since all right angles are congruent.SummaryAB ≅ segment DC∠ABC ≅ ∠DCB

Prove: segment AC ≅ segment BDSince ABCD is a rectangle, it is also a parallelogram.Since ABCD is a parallelogram, segment AB ≅ segment DC because opposite sides of a parallelogram are congruentBC ≅ BC by the Reflexive Property of Congruence.Furthermore, ∠ABC and ∠DCB are right angles by the definition of rectangle.∠ABC ≅ ∠DCB since all right angles are congruent.SummaryAB ≅ segment DC∠ABC ≅ ∠DCBBC ≅ BC

Prove: segment AC ≅ segment BDSince ABCD is a rectangle, it is also a parallelogram.Since ABCD is a parallelogram, segment AB ≅ segment DC because opposite sides of a parallelogram are congruentBC ≅ BC by the Reflexive Property of Congruence.Furthermore, ∠ABC and ∠DCB are right angles by the definition of rectangle.∠ABC ≅ ∠DCB since all right angles are congruent.SummaryAB ≅ segment DC∠ABC ≅ ∠DCBBC ≅ BCTherefore, by SAS, triangle ABC ≅ triangle DCB.

Prove: segment AC ≅ segment BDSince ABCD is a rectangle, it is also a parallelogram.Since ABCD is a parallelogram, segment AB ≅ segment DC because opposite sides of a parallelogram are congruentBC ≅ BC by the Reflexive Property of Congruence.Furthermore, ∠ABC and ∠DCB are right angles by the definition of rectangle.∠ABC ≅ ∠DCB since all right angles are congruent.SummaryAB ≅ segment DC∠ABC ≅ ∠DCBBC ≅ BCTherefore, by SAS, triangle ABC ≅ triangle DCB.Since triangle ABC ≅ triangle DCB, segment AC ≅ segment