Question

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Answer 1

See there is baar on every A and B alphabet,

A.B=AB cos theta

1=2×1 cos theta

1=2 cos theta

cos theta= 1/2

cos theta = cos 60°

therefore theta= 60°

hope this answer will help you.

Answer 2

We know

vectorA . vectorB = | A||B|cos@-----(1

given

vectorA.vectorB = 1

|A|= 2

|B|=1

put in -------(1 we get

1 = 2cos@

@ = cos^-1(1/2)

@ = cos^-1 ( cosπ/3)

@ = π/3 = 60°