Prove that diagonals of rectangle are equal in length
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Answered by
20
Let ABCD be a rectangle.
We have to prove that AC = BD.
In the triangles ABC and DCB:
BC = CB (common)
AB = DC (opposite sides of a parallelogram)
ABC =DCA = 90° (given)
so ABC ≡ DCB (SAS)
Hence AC = DB (matching sides of congruent triangles).
We have to prove that AC = BD.
In the triangles ABC and DCB:
BC = CB (common)
AB = DC (opposite sides of a parallelogram)
ABC =DCA = 90° (given)
so ABC ≡ DCB (SAS)
Hence AC = DB (matching sides of congruent triangles).
Answered by
0
Answer:
and
Step-by-step explanation:
all sides are equal (cpct)
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