Prove that diagonals of rectangles are of equal length
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Answer:
let us consider a rectangle ABCD
by pythagoras theorem,
AB²+BC²=AC²
AB²+AD²=BD²
- - -
____________
BC²-AD²=AC²-BD²
But, BC=AD,
BC²-BC²=AC²-BD²
AC²-BD²=0
AC²=BD²
AC=BD
Step-by-step explanation:
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