Prove that diagonals of rhombus bisect each other at 90 degrees
Answers
Answered by
5
Since, DOB Is a straight line,
Then, DOA +BOA =180
(DOA+BOA) =180/2 =90
So, DOA =90
BOA= 90
HENCE PROVED.......
Then, DOA +BOA =180
(DOA+BOA) =180/2 =90
So, DOA =90
BOA= 90
HENCE PROVED.......
Answered by
0
Step-by-step explanation:
Hope this will help u!
And C. P. C. T means-
Corresponding Parts of Congruent Triangle
Attachments:
Similar questions