Question

Prove that diagonals of rhombus bisect each other at 90 degrees​

Answer 1

Hey mate here is your answer...

Claim: angle AOD = angle AOB = 90

ABCD is a rhombus.

AB = AD

also, diagonals bisect each others.

DO = OB

AO is common.

So, ΔAOD congruent to ΔAOB

So, angle AOB = angle AOB (CPCT)

But angle AOD + angle AOB = 180 (Linear pair)

So, angle AOD = angle AOB =90 .

Hence ,we proved the given statement.

Hope it help you... So, Plzz mark my ans as brainliest answer...