Question

prove that each angle of a equilateral triangle measure 60 degree in. OR prove the perpendicular draw from the vertices of equal angle of an isosceles triangle sides are equal...plz answer it fast.....​

Answer 1

Step-by-step explanation:

part 1

A+B+C=180. (angle sum property)

x+x+x=180. (all the angles are equal)

3x=180

x=180/3

x=60

part 2

in ∆ ABC

angle B= angle C

BF and CD are two perpendicular

in ∆ ABF and ∆ ACD

AB=AC (isosceles triangle)

angle A=angle A (common)

angle ADC=agale AFB (both 90)

therefore both the triangls are congruent by AAS

so perpendiculars CD and BF are also equal by cpct

Mark it as brainliest answer

Answer 2

Answer:

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