prove that each angle of an equivalent triangle measures 60 degree
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Fig. is given on picture...
now,
★ GIVEN : triangle ABC is an equilateral triangle.
so, AB = BC = AC (all sides of equilateral triangle are equal).
★ TO PROVE : angle A = angle B =
angle C = 60°
★ PROOF :
as, AB = AC (given)
→ Angle C = angle B ( angles opposite to equal sides are equal) – (1)
similarly, AC = BC (given)
→ Angle B = angle A ( angles opposite to equal sides are equal) – (2)
so, from (1) & (2), we get...
Angle A = Angle B = angle C – (3)
angle A + Angle B + Angle C = 180° ( angle sum property of a triangle)
→ angle A + angle A + angle A = 180° [from (3)]
→ 3(angle A) = 180°
→ A = 180°/3
→ A = 60°
so, Angle A = Angle B = angle C = 60°
hence proved...
now,
★ GIVEN : triangle ABC is an equilateral triangle.
so, AB = BC = AC (all sides of equilateral triangle are equal).
★ TO PROVE : angle A = angle B =
angle C = 60°
★ PROOF :
as, AB = AC (given)
→ Angle C = angle B ( angles opposite to equal sides are equal) – (1)
similarly, AC = BC (given)
→ Angle B = angle A ( angles opposite to equal sides are equal) – (2)
so, from (1) & (2), we get...
Angle A = Angle B = angle C – (3)
angle A + Angle B + Angle C = 180° ( angle sum property of a triangle)
→ angle A + angle A + angle A = 180° [from (3)]
→ 3(angle A) = 180°
→ A = 180°/3
→ A = 60°
so, Angle A = Angle B = angle C = 60°
hence proved...
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