prove that each diagonal of a Rhombus bisect the angle through which the pass
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proved that each diagonal of a Rhombus bisect the angle through which the pass
Step-by-step explanation:
We will use the property that Diagonal of rhombus bisect each other
=> AO = CO
& BO = DO
in ΔAOB & ΔAOD
AO = AO ( common)
AB = AD ( equal sides of rhombus)
BO = DO
=> ΔAOB ≅ ΔAOD
=> ∠BAO = ∠DAO
hence AC Diagonal bisecting angle ∠BAD
Similarly we can show other
Hence proved that each diagonal of a Rhombus bisect the angle through which the pass
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