Question

what is the balanced equation of which stone Bridge

Answer 1

We’ve just completed the section of Higher unit 2 that investigates the behaviour of a Wheatstone Bridge. The bridge circuit is really just a pair of voltage dividers connected in parallel.  A voltmeter, ammeter or galvanometer (very sensitive ammeter) connects the two voltage divider chains together, as shown below.



When the voltage (or current) displayed on the meter is zero, we say that the Wheatstone bridge is balanced.  For a balanced bridge, it is possible to show that



[you have this proof in your notes folder]

For the circuit shown above, the voltmeter will display the difference in electrical potential between points B and D.  We can calculate this potential difference by finding the voltages at points B and D using the voltage divider equation you used for Standard Grade/Intermediate 2 Physics

The voltmeter displays the potential difference between these two points

Here is a short video that provides a recap of the Wheatstone Bridge.



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Answer 2

Hope u like my process
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For a balanced wheat stone bridge principle.

The current should not pass through the centre.

And the resistance would be in the form

$= > P \times R =Q \times S$

To prove that..

The following steps are
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=> Kirchoffs law of current.

It states that in a closed circuit the difference current from one point meeting at another is 0.

=> Kirchoffs law for potential

It states that for a circuit meeting at a junction have potential = 0

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Now .

=> Let current flow be I

=> Let resistance be P, Q, R, S

=> A Galvanometer is connected at the centre.

So..

=> Condition current flow at Galvanometer is 0.

Initially the current distribution

$=> - I_{1}P + (I - I_{1}) S +I_{g} G =0 \\ .....(since \: \: G = 0)..\\ \\ => I_{1} P = (I-I_{1} )S \\ \\ => \frac{P} {S} = \frac{I_{1} } {(I-I_{1})} .............(1)$

Similarly..

$=> I_{1}Q - I_{g} G - (I-I_{1} )R =0\\ \\.... (since \: \: G=0)....\\ \\ => I_{1 }Q =(I-I_{1 }) R \\ \\ => \frac{Q} {R} =\frac{I_{1} }{(I-I_{1 })} .........(2)$

Comparing equation 1 & 2.. We get..

$=>\frac{P}{S} =\frac{Q}{R} \\ \\ => \boxed{ \bf \: P\times R=Q\times S}$

Which is the required conditional equation for balanced wheat stone bridge.

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