prove that equal chord of congruent circle subtend equal angle at the centre
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Given
In two congruent circles,
AB = CD
To prove
<AOB = <CO'D
Proof
In ∆AOB and ∆CO'D,
AO = CO' | Radii
BO = DO' | Radii
AB = CD | Equal chords
.°. ∆AOB = ∆CO'D | By SSS congruency rule
.°. <AOB = <CO'D | By CPCT
Hence, proved .
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