prove that every point on the bisector of an angle is equidistant from the sides of the angle
Attachments:
Answers
Answered by
4
Step-by-step explanation:
we need to show BP=CP
In right angles △ABP
sinα=
AP
BP
...(i)
in right angled △ACP
sinα=
AP
CP
...(ii)
from (i) & (ii)
AP
BP
=
AP
CP
BP=CP
Similar questions