Question

Prove that expression 3x+11y and 29x+23y are divisible by 125 for the same set of values of positive x and y. find atleast 2 such pairs of x and y.
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Answer 1

Answer:

x=5,y=10

x=27,y=4

Step-by-step explanation:

3(5)+11(10)=15+110=125 which is divisible by 125.

29(5)+23(10)=145+230=275 which is divisible by 125.

3(27)+11(4)=81+44=125 and 29(27)+23(4)=783+92=875 which are divisible by 125.

Answer 2

Answer:

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