prove that F=Gm1m2/d²
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From Kepler law of planetary motion
t^2 is directly pro. to 1/ r^3
And from circular motion
F = mv^2/r
That is prove from there
t^2 is directly pro. to 1/ r^3
And from circular motion
F = mv^2/r
That is prove from there
Answered by
6
I hope it may help you.
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