Prove that f4-5J3 is an irrational number
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To prove that 4-5√3 is an irrational number, we will use the contradiction method.
Let us assume that 4 - 5√3 is a rational number with p and q as co-prime integers and q ≠ 0
⇒ 4 - 5√3 = p / q
⇒ 5√3 = 4 - p / q
⇒ √3 = (4q - p) / 5q
⇒ (4q - p) / 5q is a rational number
However, √3 is in irrational number
This leads to a contradiction that 4 - 5√3 is a rational number
Thus, 4 - 5√3 is an irrational number by contradiction method
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