prove that fcc lattice is raciprocal to bcc lattice
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bro fcc lattice and bcc lattice is such a big answer and only 5 points not fare
bikash74:
not 5 points only 2 points
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ANSWER:
The conventional unit cell for the bcc lattice has two lattice points per cell - one at (0, 0, 0) and one at (1/2, 1/2, 1/2).
To calculate the reciprocal lattice, we instead use the primitive unit cell, which has basis vectors a11 = (1/2, 1/2, -1/2), a22 = (1/2, 1/2, 1/2) and a33 = (1/2, -1/2, 1/2) when referred to the conventional cell.
The reciprocal lattice vectors can then be calculated:
b1=a2×a3a1⋅a2×a3=(1,0,1)
b2=a3×a1a1⋅a2×a3=(0,1,1)
b3=a1×a2a1⋅a2×a3=(1,1,0)
You should be able to recognise these as (scaled versions of) the primitive lattice vectors of a face-centred cubic (fcc) lattice, which is the reciprocal of a bcc lattice.
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The conventional unit cell for the bcc lattice has two lattice points per cell - one at (0, 0, 0) and one at (1/2, 1/2, 1/2).
To calculate the reciprocal lattice, we instead use the primitive unit cell, which has basis vectors a11 = (1/2, 1/2, -1/2), a22 = (1/2, 1/2, 1/2) and a33 = (1/2, -1/2, 1/2) when referred to the conventional cell.
The reciprocal lattice vectors can then be calculated:
b1=a2×a3a1⋅a2×a3=(1,0,1)
b2=a3×a1a1⋅a2×a3=(0,1,1)
b3=a1×a2a1⋅a2×a3=(1,1,0)
You should be able to recognise these as (scaled versions of) the primitive lattice vectors of a face-centred cubic (fcc) lattice, which is the reciprocal of a bcc lattice.
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