Math, asked by kotlathirumala82, 10 months ago

prove that following are irrational. 1/root2​

Answers

Answered by joshiharshin
4

Your answer is here....

Please follow me.......

Please mark me as a brainliest answer....

Attachments:
Answered by Anonymous
9

\huge\boxed{\underline{\mathcal{\red{A}\green{N}\pink{S}\orange{W}\blue{E}\pink{R}}}}

we \:have \: to \: prove \: 1 \div  \sqrt{2}  \: is \: irrational \\ let \: us \: assume \: that \: 1 \div  \sqrt{2}  \: is \: rational \\ hence.1 \div  \sqrt{2}  \: cannot \: be \: written \: in \: the \: form \: a \div b \\ where \: a \: and \: b \: (b \: not = 0) \: are \: co-prime \\ (no \: common \: factor \: other \: than \: 1) \\ hence.1 \div  \sqrt{2}  = a\div \: b

b \div a =  \sqrt{2}  \\ here \: b \div a \: is \: rational \\ \sqrt{2}   \: is \: irrational \\ since \: rational \: not \: equal \:  to \:irrational \\ therefore \: our \: assumption \: is \: incorrect \\ hence \: 1 \div  \sqrt{2}  \: is \: irrational \\ hence \: proved

Similar questions