Prove that for all positive k < 1, the equation (x + a) (x + b) = k (x + c)² has two real
roots, for any real a, b, c.
Answers
Answered by
0
Answer:
The quadratic will have real root only when its discriminant will be greater than or equal to 0
Discriminant of given equation =b
2
−4ac =(−8)
2
−4×1×k>0
⇒64−4k>0
⇒4k<64
⇒k<16
So, the value of k should be less than 16.
Answered by
0
Answer:
The quadratic will have real root only when its discriminant will be greater than or equal to 0
Discriminant of given equation =b
2
−4ac =(−8)
2
−4×1×k>0
⇒64−4k>0
⇒4k<64
⇒k<16
So, the value of k should be less than 16.
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