Question

Prove that for any four consecutive terms of an arithmetic as sequence, the sum of two terms on the two ends and the sum of two terms in the middle are same

Answer 1

Answer:

Hey Hi

Let The AP be a , a + r , a + 2r and a + 3r where r is the common difference

ATQ, sum of the two ends

= a + a + 3r

= 2a + 3r

Now sum of the middle two

= a + r + a +2r

= 2a + 3r

= sum of the two ends

Hence Proved

Hope this helps

For any doubt comment below

Stay Home Stay Safe

Regards

Rishabh Bansal