Prove that function defined as f(x) = x²-sinx+5 is continuous at x = π
Answers
Answered by
4
Answer:
Hey mate here is your answer is in image :
Attachments:
Answered by
0
Answer:
Π^2-sin180°+5
Step-by-step explanation:
Π^2-sin2×90°+0°+5
Π^2-0+5(sin0°=0)
(180)^2°+5
Similar questions