Question

Prove that
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Answer 1

Answer:

given -

cos 0=1 , cos2O

Step-by-step explanation:

square on both sides-

cos20 ,sin4 o

1 sin2o din 4 o

sin 4o sin 2o =1

now cube on both sides -

sin 12+ 0 , sin 6 0 + 3 sin =4 ,0 sin 2

sin =2, (0) = 1

sin 12 0 sin 2 this

2 sin =4, 0 +2sin 2=0 -2 =1

hence proved .

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Answer 2

Step-by-step explanation:

sin^6A+cos^6A+3sin^Acos^2A

=(sin^2)^3+(cos^2)^3+3sin^2Acos^2A

[a^3+b^3=(a+b)(a^2+b^2-ab]

=(sin^2+cos^2)(sin^4+cos^4-sin^2cos^2

cos^2

=sin^4+cos^4-sin^2cos^2+3sin^2

cos^2

=sin^4+Cos^4+2sin^2cos^2

[a^2+b^2+2ab=(a+b)^2]

=(sin^2+cos^2)^2

=(1)^2

=1 RHS

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