Prove that if a body is thrown vertically upward the time of ascent is equal to the time of descent with explanation
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t_1 = u/g ------ eq (i)
Downward motion
v = u + gt_2
v = 0 + gt_2
As the body falls back to the earth with the same velocity it was thrown vertically upward
therefore,
v = u
u = 0+ gt_2
t_2 = u/g ------- eq(ii)
now from eq (i) and (ii)
we get t_1 = t_2
Therefore,
Time ascent = Time descent
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