Math, asked by anshumangupta2212, 4 months ago

Prove that if a number is doubled then its cube is 8 time the cube of given number.​

Answers

Answered by Anonymous
3

Step-by-step explanation:

we can prove it by assume any no

let's the number be .. a

then

its double is 2a

and cube of 2a is 8 × a raised to power 3.......eq(1)

now the cube of a is .. a raised to power 3.

and when we multyply it by 8 it become

8 × a raised to power 3.....eq(2)

from eq (1) and eq (2) we get.

LHS = RHS

HENCE PROVED

Answered by yaifabachanam
10

ANSWER:

LET X BE THE GIVEN NUMBER.

THEN, IT IS GIVEN THAT X IS DOUBLE .

AND WE HAVE TO PROVE THAT ...

(2X) ^3 = 8 (X^3)

NOW,

LHS = (2X)^3

= 2^3 . X^3

= 8 (X^3)

= RHS

HENCE PROVED.

HOPE ITS HELPFUL.

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