prove that if a number is tripled then it's cube is 27 times the cube of the given number
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let a number be x. Therefore,cube of x=x^3
now new number is 3x i.e.3 times the original no..now the cube of new number=(3x)^3=27x^3=27(x^3) i.e. the cube of the new number is 27 times the cube of the original nuber.
hope my answer helped u! thank u
now new number is 3x i.e.3 times the original no..now the cube of new number=(3x)^3=27x^3=27(x^3) i.e. the cube of the new number is 27 times the cube of the original nuber.
hope my answer helped u! thank u
HimanshiKankane:
if u like my answer than please mark it as the brainliest
Answered by
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HEY UTI
FRIEND , HERE IS YOUR ANSWER
Let the no. be x ,then
According to Question,
(x+x+x)^3 = 27x^3
(3x)^3 = 27x^3
27x^3 = 27x^3
As, both the terms are equal ,
HENCE PROVED.
#AADI 93
PLZ MARK AS BRAINLIEST UTI
FRIEND , HERE IS YOUR ANSWER
Let the no. be x ,then
According to Question,
(x+x+x)^3 = 27x^3
(3x)^3 = 27x^3
27x^3 = 27x^3
As, both the terms are equal ,
HENCE PROVED.
#AADI 93
PLZ MARK AS BRAINLIEST UTI
plse mark as brainliest uti
thank u very much my friend uti
but according to me this is not the correct solution as u have equated both the terms but we have to prove that the cune of new number is 27 times the cube of original number not to eqaute both of them
cube*
my answer is correct sis
ohkk sorry but I didn't understood
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