prove that if a number is tripled ,then it's cube is 27 times the cube of the given number
Answers
Answered by
2
Let us assume that the original number = 'x'
Its cube = (x)³
= x³
If the original number is tripled then the new number = 3*x
= 3x
Cube of the new number = (3x)³= 3x*3x*3x
= 27x³
Hence,
Cube of the original number : Cube of the new number which is tripled
⇒ 1 : 27
Hence, the cube of the new number is 27 times the cube of the original number.
Hence proved
Answered by
9
HEYA!
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Let the number be x
![cube \: of \: number \: = x {}^{3} \\ \\ now \: \: three \: \: times \: \: the \: \: number \: = 3x \\ cube \: of \: 3x = (3x) {}^{3} \\ \\ = > 27x {}^{3} cube \: of \: number \: = x {}^{3} \\ \\ now \: \: three \: \: times \: \: the \: \: number \: = 3x \\ cube \: of \: 3x = (3x) {}^{3} \\ \\ = > 27x {}^{3}](https://tex.z-dn.net/?f=cube+%5C%3A+of+%5C%3A+number+%5C%3A++%3D+x+%7B%7D%5E%7B3%7D++%5C%5C++%5C%5C+now+%5C%3A++%5C%3A+three+%5C%3A++%5C%3A+times+%5C%3A++%5C%3A+the+%5C%3A++%5C%3A+number+%5C%3A++%3D+3x+%5C%5C+cube+%5C%3A+of+%5C%3A+3x+%3D+%283x%29+%7B%7D%5E%7B3%7D++%5C%5C++%5C%5C++%3D++%26gt%3B+27x+%7B%7D%5E%7B3%7D+)
Hence it is 27 times the cube of x.
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Let the number be x
Hence it is 27 times the cube of x.
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